// One-star problem
// Problem 10190 Divide, But Not Quite Conquer!
/*
This program is written by
Prof. Chua-Huang Huang
Department of Information Engineering and Computer Science
Feng Chia University
Taichung, Taiwan
Disclaimer:
The programming problem is downloaded from UVa Online Judge (https://uva.onlinejudge.org/).
The program solution is provided for helping students to prepare Collegiate Programming
Examination (CPE). The author does not guarantee the program is completely correct to pass
UVa Online Judge platform or CPE examination platform.
This program is not intended for a student to copy only. He/She should practice the
programming problem himself/herself. Only use the program solution as a reference.
The author is not responsible if the program causes any damage of your computer or
personal properties.
No commercial use of this program is allowed without the author's written permission.
*/
#include
#include
int main(void) {
int m, n; // Maximum value of m and n is 2,147,483,647 which is greater than 2000000000.
int term, next;
int conquered;
while (scanf("%d %d", &n, &m)==2) { // Read in m and n if there are more input data.
term = n; // Initail the first element of the sequence a1=n.
while (term!=1) { // When the element of the sequence reaches 1, succeed and stop.
if (term%m==0) { // If a[i] is divisible by m,
term = term / m; // Set the next term a[i+1] to be term / m.
}
else break; // If a[i] is not 1 and not divided by m, fail and stop.
}
if (term==1) { // This means the sequence exists.
term = n; // Initial a[1].
printf("%d ", term); // Print a[1].
while (term!=1) { // a[i]!=1, continue.
term = term / m; // Compute a[i+1].
printf("%d ", term); // Print a[i+1].
}
printf("\n"); // Print a new line.
}
else printf("Boring!\n"); // The process fails, print "Boring!".
}
return 0;
}