// One-star problem
// Problem 10221 Satellites
/*
This program is written by
Prof. Chua-Huang Huang
Department of Information Engineering and Computer Science
Feng Chia University
Taichung, Taiwan
Disclaimer:
The programming problem is downloaded from UVa Online Judge (https://uva.onlinejudge.org/).
The program solution is provided for helping students to prepare Collegiate Programming
Examination (CPE). The author does not guarantee the program is completely correct to pass
UVa Online Judge platform or CPE examination platform.
This program is not intended for a student to copy only. He/She should practice the
programming problem himself/herself. Only use the program solution as a reference.
The author is not responsible if the program causes any damage of your computer or
personal properties.
No commercial use of this program is allowed without the author's written permission.
*/
#include
#include
#include
#include
// 1 pi = 180 degrees; 1 degree = 60 minutes.
// Convert degree to radian, d degree = (d/180)*pi radian.
// Convert minute to radian, m minutes = (m/(60*180))*pi radian.
// The solution: arc = r*a and chord = 2r sin(a/2),
// where r is the radius, i.e., the distance from the center of earth center, a is the angle in radian.
int main(void) {
double distance, angle;
char unit[4];
while (scanf("%lf %lf %s", &distance, &angle, &unit)==3) { // Input distance from earth surface, angle, and unit.
distance = distance + 6440.0; // The earth radius is 6440 KM, the distance is from the earth center.
if (strcmp(unit,"deg")==0)
printf("%8.6lf %8.6lf\n", distance * (angle / 180.0) * 3.14159, // Arc length in degree
2 * distance *sin((angle / 180.0) * 3.14159 / 2.0)); // Chord length in degree
if (strcmp(unit,"min")==0)
printf("%8.6lf %8.6lf\n", distance * (angle / (180.0 * 60)) * 3.14159, // Arc length in minute
2 * distance * sin((angle / (180.0 * 60)) * 3.14159 / 2.0)); // Chord length in minute
}
return 0;
}